The minimum value of 2 sin 6x+cos 6x
WebOct 26, 2016 · So we can then write the initial equation: sin6x +cos6x = 1 −3sin2xcos2 as: S3 +(1 −S)3 = 1 − 3S(1 − S) ∴ S3 +1 −3S +3S2 − S3 = 1 −3S +3S2 ∴ 0 = 0 What does this mean! well it means the initial equation is true for all vales of x. Hence it is not an equation that can be solved, but rather it is an identity. Answer link P dilip_k Oct 28, 2016 WebFree math problem solver answers your trigonometry homework questions with step-by-step explanations.
The minimum value of 2 sin 6x+cos 6x
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WebJan 25, 2024 · answered Jan 25, 2024 by Rohit Singh (65.4k points) We know that. => sin2A+cos2A=1. => 1-sin2A=cos2A. => 1-cos2A=sin2A. Applying these and solving we have: =2 (sin6A+cos6A)-3 (sin4A+cos4A)+1. =2sin6A+2cos6A-3sin4A-3cos4A+sin2A+cos2A. =2sin6A+2cos6A-2sin4A-2cos4A-sin4A-cos4A+sin2A+cos2A. WebFree Minimum Calculator - find the Minimum of a data set step-by-step
WebSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. WebArithmetic Mean Geometric Mean Quadratic Mean Median Mode Order Minimum Maximum Probability Mid-Range Range Standard Deviation Variance Lower ... Finance. Simple Interest Compound Interest Present Value Future Value. Economics. Point of Diminishing Return. Conversions. Decimal to Fraction Fraction to Decimal Radians to ... \int \sin(6x)\cos(6x ...
WebSimplify -cos (6x)sin (6x) Mathway Calculus Examples Popular Problems Calculus Simplify -cos (6x)sin (6x) − cos(6x)sin(6x) - cos ( 6 x) sin ( 6 x) Nothing further can be done with this topic. Please check the expression entered or try another topic. −cos(6x)sin(6x) - cos ( … WebFeb 18, 2024 · Explanation: Use trig identity: cosa − cosb = − 2sin( a + b 2)sin( a − b 2) In this case: a +b 2 = 4x. a −b 2 = 2x. cos(2x) − cos(6x) = 2sin(4x).sin(2x) = 0. a. sin2x = 0 --> Unit circle gives --> 2x = kπ. x = kπ 2.
WebSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.
Web{For the maximum value, The second term, [3* (sin^2x)* (cos^2x)] must be minimum, which is only when x is 0. Therefore the product of sine and cosine term will be equal to 0. } =1–0 Hence, the maximum value is 1. 2 Dheeraj Reddy Lives in Bengaluru, Karnataka, India Upvoted by Chetna Kesarwani bus beim computerWebJul 6, 2024 · The value of the integral π/2 ∫ −π/2 dx (1+ex)(sin6x+cos6x) ∫ − π / 2 π / 2 d x ( 1 + e x) ( s i n 6 x + c o s 6 x) is equal to (A) 2π (B) 0 (C) π (D) π/2 jee main 2024 Share It On 1 Answer +1 vote answered Jul 6, 2024 by GovindSaraswat (45.5k points) selected Jul 6, 2024 by Swetakeshri Best answer Correct option is (C) π hana on fbi most wantedWebClick here👆to get an answer to your question ️ Express u = sin^6x + cos^6x in the form A + Bcos4x ,where A and B are constants.Find A and B . Hence obtain the maximum and minimum value of u . Solve Study Textbooks Guides. Join / Login. ... sin 6 x = sin 4 x − sin 2 x Find the value of x. hana optimised contentWebMar 23, 2016 · Here is the expression: 2 ( sin 6 x + cos 6 x) − 3 ( sin 4 x + cos 4 x) + 1 The exercise is to evaluate it. In my text book the answer is 0 I tried to factor the expression, but it got me nowhere. algebra-precalculus trigonometry Share Cite Follow edited Mar 23, 2016 at 13:34 Jean-Claude Arbaut 22.7k 7 50 82 asked Mar 23, 2016 at 13:11 Planet_Earth hana on premise vs cloudWebWrite the expression in terms of sine only. sin 6x + cos 6x Submit Answer 4. [1/2 Points] DETAILS PREVIOUS ANSWERS SPRECALC7 7.2.020.MI. Use an Addition or Subtraction Formula to write the expression as a trigonometric function of one number. 13л 131 sin x Find its exact value. 1 2 Need Help? Read It Master It Submit Answer hana oracle 違いWebMar 24, 2024 · Suppose we've got cosine of angle A and B measurements. Then, we have: If we get A = B, then: Since we're specified the equation . Thus, by the above specified conclusion, we get; Since cosine has period of radians, therfore we get: where n is an integer. Thus, the value of B which for the expression cos^2(6x)-sin^2(6x)=cos(B) is B = 12x + 2πn bus belfast to comberWebI have sin 2 x = 2 3 , and I'm supposed to express sin 6 x + cos 6 x as a b where a, b are co-prime positive integers. This is what I did: First, notice that ( sin x + cos x) 2 = sin 2 x + cos 2 x + sin 2 x = 1 + 2 3 = 5 3 . Now, from what was given we have sin x … bus being towed