WebMay 7, 2024 · In C++, global variable (if we have a local variable with same name), can be accessed using scope resolution operator (::). What will be the output of this program? #include using namespace std; int a = 90; int fun (int x, int *y = &a) { *y = x + *y; return x + *y; } int main () { int a = 5, b = 10; a = fun (a); WebMar 26, 2024 · 6.1k views asked Mar 26, 2024 in Mathematics by MukeshKumar (32.2k points) Let I n = e ∫ 1 x19(log x )ndx, I n = ∫ 1 e x 19 ( l o g x ) n d x, where n ∈ N. If (20)I10 = αI9 + βI8, for natural numbers α and β, then α - β equal to _____. jee jee main jee main 2024 Please log in or register to answer this question. 1 Answer +1 vote
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Let In = ∫ x^(19) (log x )^n dx, where n ∈ N. If (20)I10 = αI9 + βI8 ...
WebThe definite integral of f (x) f ( x) from x = a x = a to x = b x = b, denoted ∫b a f (x)dx ∫ a b f ( x) d x, is defined to be the signed area between f (x) f ( x) and the x x axis, from x= a x = a to … WebNov 1, 2024 · Answer: There are some errors so far i know.. 1. You can not declare a variable data type after "using namespace std", but in main or classes...etc...however its answer … Webx19. through . x23. bne x22, x23, Else // go to Else if i !=j add x19, x20, x21 // f=g+h beq x0, x0, Exit // go to Exit Else: sub x19, x20, x21 // f=g-h Exit: Example 2: while (save[i] == k) i += 1; assume value of. i . is in register . x22. and value of . k. is in register . x24. Assume base of array . save[] is in . x25. loop: slli x10, x22 ... peter pan 75th street